10th Maths Quarterly Exam 2026 Question Paper & Answer Key | Coimbatore District (EM)

Fine-tune your exam preparation with the official 10th Maths Quarterly Exam 2026 Question Paper curated for schools across the Coimbatore District. This district-level evaluation paper serves as a vital benchmark for Tamil Nadu Samacheer Kalvi state board students aiming to cross-verify their analytical skills before major terminal assessments. The question paper provides thorough coverage of early high-yield topics, including Relations and Functions, Numbers and Sequences, fundamental Algebra matrices, and coordinate Geometry theorems. By working through this specific paper alongside the comprehensive answer keys, you can review the exact step-by-step marking schemes, refine your formula application skills, and master the structured presentation methods necessary to achieve a perfect centum score on your final board examinations.


10th Maths Quarterly Exam 2026 Question Paper & Answer Key | Coimbatore District

QUARTERLY EXAMINATION

10th Std • MATHEMATICS
TIME: 3.00 hrs. MARKS: 100
PART - I • I. CHOOSE THE CORRECT ANSWER: 14 × 1 = 14

1. If A = {1, 2}, B = {1, 2, 3, 4}, C = {5, 6} and D = {5, 6, 7, 8} then state which of the following statement is true.
a) (A × C) ⊂ (B × D)      b) (B × D) ⊂ (A × C)
c) (A × B) ⊂ (A × D)      d) (D × A) ⊂ (B × A)

2. The Range of the relation R = {(x, x2) | x is a prime number less than 13} is
a) {2, 3, 5, 7}      b) {2, 3, 5, 7, 11}      c) {4, 9, 25, 49, 121}      d) {1, 4, 9, 25, 49, 121}

3. Let A = {1, 2, 3, 4} and B = {4, 8, 9, 10}. A function f: A → B given by f = {(1, 4), (2, 8), (3, 9), (4, 10)} is a
a) Many-one function      b) Identity function      c) One-to-one function      d) Into function

4. Using Euclid's division lemma, if the cube of any positive integer is divided by 9 then the possible remainders are
a) 0, 1, 8      b) 1, 4, 8      c) 0, 1, 3      d) 1, 3, 5

5. If tn is the nth term of an A.P then t2n − tn is
a) nd      b) 2nd      c) 2d      d) 3nd

6. The next term of the sequence 3/16, 1/8, 1/12, 1/18, ... is
a) 1/24      b) 1/27      c) 2/3      d) 1/81

7. The solution of the system x + y − 3z = −6, −7y + 7z = 7, 3z = 9 is
a) x = 1, y = 2, z = 3      b) x = −1, y = 2, z = 3
c) x = −1, y = −2, z = 3      d) x = 1, y = −2, z = 3

8. Which of the following should be added to make x4 + 64 a perfect square
a) 4x2      b) 16x2      c) 8x2      d) −8x2

9. If ax2 + bx + c = 0 has equal roots, then c is equal to
a) b2 / (2a)      b) b2 / (4a)      c) −b2 / (2a)      d) −b2 / (4a)

10. If in triangle ABC and EDF, AB / DE = BC / FD then they will be similar, when
a) ∠B = ∠E      b) ∠A = ∠D      c) ∠B = ∠D      d) ∠A = ∠F

11. The straight line given by the equation x = 11 is
a) Parallel to X axis      b) passing through the origin
c) parallel to Y axis      d) passing through the point (0, 11)

12. If the slope of the line PQ is 1 / √3 then slope of the perpendicular bisector of PQ is
a) √3      b) −√3      c) 1 / √3      d) 0

13. When proving that a quadrilateral is a trapezium, it is necessary to show
a) Two sides are parallel      b) Two parallel and two non-parallel sides
c) Opposite sides are parallel      d) All sides are of equal length

14. The value of sin2θ + 1 / tan2θ is equal to
a) tan2θ      b) 1      c) cot2θ      d) 0

PART - II • II. Answer any 10 of the following questions (Q.No. 28 is compulsory): 10 × 2 = 20

15. If A = {m, n}, B = ∅ then find A × B and A × A.

16. Let X = {1, 2, 3, 4} and Y = {2, 4, 6, 8, 10} and R = {(1, 2), (2, 4), (3, 6), (4, 8)}. Show that R is a function and find its domain, co-domain and range?

17. If f(x) = x2 − 1, g(x) = x − 2 find a, if g ∁ f(a) = 1.

18. Solve: 5x ≡ 4 (mod 6).

19. Find the number of terms in the A.P. 3, 6, 9, 12, ..., 111.

20. Find the sum of 2 + 4 + 6 + ... + 80.

21. Find the excluded values of the expression (7p + 2) / (8p2 + 13p + 5).

22. Find the LCM of 9a3b2, 12a2b2c.

23. If ΔABC is similar to ΔDEF such that BC = 3 cm, EF = 4 cm and area of ΔABC = 54 cm2. Find the area of ΔDEF.

24. Find the slope of a line joining the points (5, √5) with the origin.

25. Find the equation of a line joining the points (3, −4) and having slope −5/7.

26. If the straight lines 12y = −(p + 3)x + 12 and 12x − 7y = 16 are perpendicular then find 'p'.

27. Prove: √[(1 + sin θ) / (1 − sin θ)] = sec θ + tan θ.

28. If P = x / (x + y) and Q = y / (x + y) then find 1 / (P2 − Q2).

PART - III • III. Answer any 10 of the following questions (Q.No. 42 is compulsory): 10 × 5 = 50

29. Given A = {1, 2, 3}, B = {2, 3, 5}, C = {3, 4} and D = {1, 3, 5}, check if (A ∩ C) × (B ∩ D) = (A × B) ∩ (C × D) is true?

30. Let f: A → B be a function defined by f(x) = (x / 2) − 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by
(i) set of ordered pairs      (ii) a table      (iii) an arrow diagram      (iv) a graph

31. If the function f: R → R is defined by
f(x) = 2x + 7  ;  x < −2
f(x) = x2 − 2  ;  −2 ≤ x < 3
f(x) = 3x − 2  ;  x ≥ 3
then find the values of:    (i) f(4)    (ii) f(−2)    (iii) f(4) + 2f(1)    (iv) [f(1) − 3f(4)] / f(−3)

32. The sum of three consecutive terms that are in A.P. is 27 and their product is 288. Find the three terms.

33. Rekha has 15 square colour papers of sizes 10 cm, 11 cm, 12 cm, ..., 24 cm. How much area can be decorated with these colour papers?

34. Find the sum of all natural numbers between 300 and 600 which are divisible by 7.

35. Find the square root of 64x4 − 16x3 + 17x2 − 2x + 1.

36. Simplify: [1 / (x2 − 5x + 6)] + [1 / (x2 − 3x + 2)] − [1 / (x2 − 8x + 15)]

37. If α, β are the roots of the equation 3x2 + 7x − 2 = 0, find the values of:
(i) (α / β) + (β / α)      (ii) (α2 / β) + (β2 / α)

38. State and prove basic proportionality theorem.

39. Find the area of the quadrilateral formed by the points (8, 6), (5, 11), (−5, 12) and (−4, 3).

40. Find the equation of the perpendicular bisector of the line joining the points A(−4, 2) and B(6, −4).

41. Prove: [(sin3A + cos3A) / (sin A + cos A)] + [(sin3A − cos3A) / (sin A − cos A)] = 2.

42. A line makes positive intercepts on coordinate axes whose sum is 7 and it passes through (−3, 8). Find its equation.

PART - IV • Answer the following: 2 × 8 = 16

43. a) Construct a triangle similar to a given triangle LMN with its sides equal to 4/5 of the corresponding sides of the triangle LMN (Scale factor 4/5 < 1).
(OR) b) Construct a ΔPQR in which PQ = 8 cm, ∠R = 60°, and the median RG from R to PQ is 5.8 cm. Find the length of the altitude from R to PQ.

44. a) A bus is travelling at a uniform speed of 50 km/hr. Draw the time-distance graph and hence find:
    (i) the constant of variation.
    (ii) how far will it travel in 90 minutes?
    (iii) the time required to cover a distance of 300 km from the graph.
(OR) b) Draw the graph of xy = 24, where x, y > 0. Using the graph, find:
    (i) y when x = 3 and
    (ii) x when y = 6.

KEY ANSWERS
I. Choose:

1. a) (A × C) ⊂ (B × D)

2. c) {4, 9, 25, 49, 121}

3. c) One-to-one function

4. a) 0, 1, 8

5. a) nd

6. b) 1/27

7. a) x = 1, y = 2, z = 3

8. b) 16x2

9. b) b2 / (4a)

10. c) ∠B = ∠D

11. c) parallel to Y axis

12. b) −√3

13. b) Two parallel and two non-parallel sides

14. b) 1

II. Answer any 10:

15. A × B = {m, n} × ∅ = ∅
A × A = {(m, m), (m, n), (n, m), (n, n)}

16. Domain = {1, 2, 3, 4}
Co-domain = {2, 4, 6, 8, 10}
Range = {2, 4, 6, 8}

17. f(x) = x2 − 1, g(x) = x − 2
g ∁ f(a) = f(a) − 2 = a2 − 1 − 2 = a2 − 3
a2 − 3 = 1 ⇒ a2 = 4 ⇒ a = ±2

18. 5x ≡ 4 (mod 6)
5x − 4 = 6n ⇒ x = 2, 8, 14, ...

19. a = 3, d = 3, l = 111
n = [(l − a) / d] + 1 = [(111 − 3) / 3] + 1 = (108 / 3) + 1 = 36 + 1 = 37

20. Sum = 2 + 4 + 6 + ... + 80
= 2(1 + 2 + 3 + ... + 40) = 2 × [(40 × 41) / 2] = 1640

21. (7p + 2) / (8p2 + 13p + 5) = (7p + 2) / [(p + 1)(8p + 5)]
(p + 1)(8p + 5) = 0 ⇒ p = −1 or p = −5/8
Excluded values are −1, −5/8

22. LCM of 9a3b2, 12a2b2c = 36a3b2c

23. Area(ΔABC) / Area(ΔDEF) = BC2 / EF2
54 / Area(ΔDEF) = 32 / 42 = 9 / 16
Area(ΔDEF) = (54 × 16) / 9 = 96 cm2

24. Slope m = (y2 − y1) / (x2 − x1) = (0 − √5) / (0 − 5) = √5 / 5 = 1 / √5

25. y − y1 = m(x − x1) ⇒ y + 4 = −5/7 (x − 3)
7y + 28 = −5x + 15 ⇒ 5x + 7y + 13 = 0

26. m1 = −(p + 3) / 12,   m2 = −12 / (−7) = 12/7
m1 × m2 = −1 ⇒ [−(p + 3) / 12] × (12 / 7) = −1
p + 3 = 7 ⇒ p = 4

27. LHS = √[ (1 + sin θ) / (1 − sin θ) × (1 + sin θ) / (1 + sin θ) ]
= √[ (1 + sin θ)2 / (1 − sin2θ) ] = √[ (1 + sin θ)2 / cos2θ ]
= (1 + sin θ) / cos θ = (1 / cos θ) + (sin θ / cos θ) = sec θ + tan θ = RHS. Hence proved.

28. P = x / (x + y),   Q = y / (x + y)
P2 − Q2 = (x2 − y2) / (x + y)2 = [(x + y)(x − y)] / (x + y)2 = (x − y) / (x + y)
1 / (P2 − Q2) = (x + y) / (x − y)

III. Answer any 10:

29. LHS: (A ∩ C) = {3},   (B ∩ D) = {3, 5}
(A ∩ C) × (B ∩ D) = {(3, 3), (3, 5)} — (1)
RHS: A × B = {(1, 2), (1, 3), (1, 5), (2, 2), (2, 3), (2, 5), (3, 2), (3, 3), (3, 5)}
C × D = {(3, 1), (3, 3), (3, 5), (4, 1), (4, 3), (4, 5)}
(A × B) ∩ (C × D) = {(3, 3), (3, 5)} — (2)
From (1) and (2), (A ∩ C) × (B ∩ D) = (A × B) ∩ (C × D) is True.

30. f(x) = (x / 2) − 1
f(2) = 0,   f(4) = 1,   f(6) = 2,   f(10) = 4,   f(12) = 5
(i) Set of ordered pairs: f = {(2, 0), (4, 1), (6, 2), (10, 4), (12, 5)}
(ii) A table:
x2461012
f(x)01245
(iii) An arrow diagram: 2→0, 4→1, 6→2, 10→4, 12→5
(iv) A graph: Plot the points (2, 0), (4, 1), (6, 2), (10, 4), (12, 5) on Cartesian plane.

31.
(i) f(4) = 3(4) − 2 = 12 − 2 = 10
(ii) f(−2) = (−2)2 − 2 = 4 − 2 = 2
(iii) f(4) + 2f(1) = 10 + 2(−1) = 10 − 2 = 8
(iv) [f(1) − 3f(4)] / f(−3) = [−1 − 30] / [2(−3) + 7] = −31 / 1 = −31

32. Sum = (a − d) + a + (a + d) = 27 ⇒ 3a = 27 ⇒ a = 9
Product = (a − d)a(a + d) = 288 ⇒ (a2 − d2)a = 288
(81 − d2)9 = 288 ⇒ 81 − d2 = 32 ⇒ d2 = 49 ⇒ d = ±7
Three terms are: 2, 9, 16 or 16, 9, 2

33. Total Area = 102 + 112 + 122 + ... + 242
= (12 + 22 + ... + 242) − (12 + 22 + ... + 92)
= [(24 × 25 × 49) / 6] − [(9 × 10 × 19) / 6] = 4900 − 285 = 4615 cm2

34. a = 301, d = 7, l = 595
n = [(l − a) / d] + 1 = [(595 − 301) / 7] + 1 = (294 / 7) + 1 = 42 + 1 = 43
S43 = (43 / 2) [301 + 595] = (43 / 2) × 896 = 43 × 448 = 19264

35. Square root of 64x4 − 16x3 + 17x2 − 2x + 1 by division method gives quotient 8x2 − x + 1
√(64x4 − 16x3 + 17x2 − 2x + 1) = |8x2 − x + 1|

36. [1 / ((x − 2)(x − 3))] + [1 / ((x − 2)(x − 1))] − [1 / ((x − 5)(x − 3))]
= [(x − 1)(x − 5) + (x − 3)(x − 5) − (x − 1)(x − 2)] / [(x − 1)(x − 2)(x − 3)(x − 5)]
= (x2 − 6x + 5 + x2 − 8x + 15 − x2 + 3x − 2) / [(x − 1)(x − 2)(x − 3)(x − 5)]
= (x2 − 11x + 18) / [(x − 1)(x − 2)(x − 3)(x − 5)]
= [(x − 9)(x − 2)] / [(x − 1)(x − 2)(x − 3)(x − 5)] = (x − 9) / [(x − 1)(x − 3)(x − 5)]

37. 3x2 + 7x − 2 = 0 ⇒ α + β = −7/3,   αβ = −2/3
(i) (α / β) + (β / α) = (α2 + β2) / αβ = [(α + β)2 − 2αβ] / αβ = [(−7/3)2 − 2(−2/3)] / (−2/3) = (49/9 + 4/3) × (−3/2) = (61/9) × (−3/2) = −61/6
(ii) (α2 / β) + (β2 / α) = (α3 + β3) / αβ = [(α + β)3 − 3αβ(α + β)] / αβ = [(−7/3)3 − 3(−2/3)(−7/3)] / (−2/3) = 469/18

38. State and Prove Basic Proportionality Theorem (Thales Theorem) — Refer Textbook.

39. Area of quadrilateral = 1/2 [(x1y2 + x2y3 + x3y4 + x4y1) − (x2y1 + x3y2 + x4y3 + x1y4)]
Points: (8, 6), (5, 11), (−5, 12), (−4, 3)
= 1/2 [(88 + 60 − 15 − 24) − (30 − 55 − 48 + 24)] = 1/2 [109 − (−49)] = 1/2 (158) = 79 sq. units

40. Midpoint of AB, D = [(−4 + 6) / 2, (2 − 4) / 2] = (1, −1)
Slope of AB = (−4 − 2) / [6 − (−4)] = −6 / 10 = −3/5
Slope of perpendicular bisector m = 5/3
Equation: y − y1 = m(x − x1) ⇒ y + 1 = 5/3 (x − 1)
3y + 3 = 5x − 5 ⇒ 5x − 3y − 8 = 0

41. LHS = [(sin A + cos A)(sin2A − sin A cos A + cos2A)] / (sin A + cos A) + [(sin A − cos A)(sin2A + sin A cos A + cos2A)] / (sin A − cos A)
= (1 − sin A cos A) + (1 + sin A cos A) = 1 + 1 = 2 = RHS. Hence proved.

42. Sum of intercepts = 7 ⇒ a + b = 7 ⇒ b = 7 − a
Equation: (x / a) + [y / (7 − a)] = 1
Passes through (−3, 8): [−3 / a] + [8 / (7 − a)] = 1 ⇒ −3(7 − a) + 8a = a(7 − a)
−21 + 3a + 8a = 7a − a2 ⇒ a2 + 4a − 21 = 0 ⇒ (a + 7)(a − 3) = 0
Since intercepts are positive, a = 3 ⇒ b = 7 − 3 = 4
Equation: (x / 3) + (y / 4) = 1 ⇒ 4x + 3y − 12 = 0

Part - IV Key:

43. a) Refer Textbook • b) Refer Textbook

44. a)
Time (min) x60120180240300360
Distance (km) y50100150200250300
(i) Constant of variation: k = y / x = 50 / 60 = 5/6
(ii) Distance for 90 minutes = 75 km
(iii) Time required to cover 300 km = 360 minutes (6 hrs)
44. b)
x1234681224
y2412864321
xy = 24 ⇒ k = 24
(i) When x = 3 ⇒ y = 8
(ii) When y = 6 ⇒ x = 4

10th Study Materials

10th Std Study Materials

10th Tamil Study Materials

10th English Study Materials

10th Maths Study Materials

10th Science Study Materials

10th Social Science Study Materials


10th Question Papers & Answer Keys

10th Quarterly Exam Question Papers and Answer Keys

10th Half Yearly Exam Question Papers and Answer Keys

10th Public Exam Question Papers and Answer Keys

10th First Revision Test Question Papers and Answer Keys

10th Second Revision Test Question Papers and Answer Keys

10th Third Revision Test Question Papers and Answer Keys

10th First MidTerm Test Question Papers and Answer Keys

10th Second MidTerm Test Question Papers and Answer Keys

Important Links

10th Syllabus

10th Lesson Plans

10th Monthly Test & Unit Test

Tamilnadu 10th Time Table | SSLC Exam Time table

Next Post Previous Post
No Comment
Add Comment
comment url