10th Maths Quarterly Exam 2026 Question Paper & Answer Key | Dharmapuri District (EM)

Evaluate your mathematical skills with the official 10th Maths Quarterly Exam 2026 Question Paper specifically prepared for schools in the Dharmapuri District of Tamil Nadu. This district-level terminal test offers students a premier resource to assess their conceptual understanding of foundational high school mathematics. Curated under the Samacheer Kalvi state curriculum framework, this assessment focuses on high-weightage chapters including Relations and Functions, Numbers and Sequences, Algebra, and Geometry matrices. Utilizing the accompanying detailed key solutions allows you to cross-verify structural proof layouts, correct minor calculation errors, and master the exact step-by-step presentation metrics required to score centum in your final board examinations.


10th Maths Quarterly Exam 2026 Question Paper & Answer Key | Dharmapuri District

Dharmapuri - (D.E.O)

QUARTERLY EXAMINATION - 2026

10. Std MATHEMATICS Reg.No: [________]
Time: 3.00 HOUR MARKS: 100
Instructions:
  • Write clearly and legibly without mistakes and overwriting utilising the maximum time allotted for the exam
  • Answers should be in your own style without changing the main core concept.
  • Use only black or blue ink pen to write the exam.
  • Draw clear diagrams wherever necessary.
PART - I • Choose the Correct answer 14 × 1 = 14

1. If n(A × B) = 6 and A = {1, 3} then n(B) is
a) 1      b) 2      c) 3      d) 6

2. If {(a, 8), (6, b)} represents an identity function, then the value of a and b are respectively
a) (8, 6)      b) (8, 8)      c) (6, 8)      d) (6, 6)

3. If f: A → B is a bijective function and if n(B) = 7, then n(A) is equal to
a) 7      b) 49      c) 1      d) 14

4. Let n(A) = m and n(B) = n then the total number of functions that can be defined from A to B is
a) mn      b) nm      c) 2mn − 1      d) 2m

5. The sum of the exponents of the prime factors in the prime factorization of 1729 is
a) 1      b) 2      c) 3      d) 4

6. Given F1 = 1, F2 = 3 and Fn = Fn−1 + Fn−2 then F5 is
a) 3      b) 5      c) 8      d) 11

7. If 6 times of 6th term of an A.P is equal to 7 times the 7th term then the 13th term of the A.P is
a) 0      b) 6      c) 7      d) 13

8. The Value of (13 + 23 + 33 + ... + 153) − (1 + 2 + 3 + ... + 15) is
a) 14400      b) 14200      c) 14280      d) 14520

9. The square root of (256 x8 y4 z10) / (25 x6 y4 z8) is equal to
a) 16/5 |(x2 z2) / y2|      b) 16 |y2 / (x2 z4)|      c) 16/5 |y / x2|      d) 16/5 |(x z2) / y|

10. Which of the following should be added to make x4 + 64 a perfect square
a) 4x2      b) 16x2      c) x2      d) −8x2

11. Graph of a linear equation is a
a) Straight line      b) Circle      c) Parabola      d) None of the above

12. In ΔLMN, ∠L = 60°, ∠M = 50°. If ΔLMN ~ ΔPQR then the value of ∠R is
a) 40°      b) 70°      c) 30°      d) 110°

13. The area of triangle formed by the points (−5, 0) (0, −5) and (5, 0) is
a) 0 Sq.units      b) 25 Sq.units      c) 5 Sq.units      d) None of these

14. If (5, 7), (3, P) and (6, 6) are collinear, then find the value of P is
a) 3      b) 6      c) 9      d) 12

PART - II • Answer any Ten of the following (Q.No.28 is Compulsory). 10 × 2 = 20

15. Let A = {1, 2, 3} and B = {x | x is a prime number less than 10}. Find A × B and B × A

16. Show that the function f: N → N defined by f(m) = m2 + m + 3 is one - one function.

17. Find k if f∁f(k) = 5, Where f(k) = 2k − 1

18. Find all positive integers, when divided by 3 leaves remainder 2.

19. Find the least number that is divisible by the first ten natural numbers.

20. Compute x, such that 104 ≡ x (mod 19).

21. If 3 + k, 18 − k, 5k + 1 are in A.P then find k

22. How many terms of the series 1 + 5 + 9 + ... must be taken so that their sum is 190?

23. Find the area of the triangle formed by point (1, −1) (−4, 6) and (−3, −5).

24. Simplify: [(4x2y) / (2z2)] × [(6xz3) / (20y4)]

25. Find the sum and Product of the roots of x2 + 8x − 65 = 0

26. If ΔABC is similar to ΔDEF such that BC = 3 Cm, EF = 4 Cm and area of ΔABC = 54 Cm2, find the area of ΔDEF

27. Find the equation of a line through the given pair of points (2, 3) and (−7, −1)

28. If 13824 = 2a × 3b then find a and b.

PART - III • Answer any Ten of the following (Q.No.42 is Compulsory). 10 × 5 = 50

29. Let A = The set of all natural numbers less than 8, B = The set of all prime numbers less than 8, C = The set of even prime number. Verify that (A ∩ B) × C = (A × C) ∩ (B × C)

30. Let f: A → B be a function defined by f(x) = (x / 2) − 1, where A = {2, 4, 6, 10, 12}, B = {0, 1, 2, 4, 5, 9}. Represent f by
i) Set of ordered pairs      ii) a table      iii) an arrow diagram      iv) a graph

31. If the function f: R → R is defined by
f(x) = 2x + 7 ; x < −2
f(x) = x2 − 2 ; −2 ≤ x < 3
f(x) = 3x − 2 ; x ≥ 3
then find the values of:    i) f(4)    ii) f(−2)    iii) f(4) + 2f(1)    iv) [f(1) − 3f(4)] / f(−3)

32. Consider the functions f(x) = x − 4, g(x) = x2 and h(x) = 3x − 5 show that (f ∁ g) ∁ h = f ∁ (g ∁ h)

33. If p1x1 × p2x2 × p3x3 × p4x4 = 113400 where p1, p2, p3, p4 are primes in ascending order and x1, x2, x3, x4 are integers, find the value of p1, p2, p3, p4 and x1, x2, x3, x4.

34. The sum of three consecutive terms that are in A.P is 27 and their product is 288. Find the three terms.

35. Find the sum of n terms of the series: 5 + 55 + 555 + ...

36. Rekha has 15 Square colour papers of sizes 10 cm, 11 cm, 12 cm, ..., 24 cm. How much area can be decorated with these colour papers?

37. Find the area of the quadrilateral formed by the points (8, 6) (5, 11) (−5, 12), (−4, 3)

38. Solve: 3x − 2y + z = 2, 2x + 3y − z = 5, x + y + z = 6

39. Simplify: [1 / (x2 − 5x + 6)] + [1 / (x2 − 3x + 2)] − [1 / (x2 − 8x + 15)]

40. If 9x4 + 12x3 + 28x2 + ax + b is a perfect square, find the values of a and b.

41. State and Prove Thales Theorem.

42. Find the equation of a straight line passing through the point (6, −2) and perpendicular to the line joining the points (6, 7) and (2, −3).

PART - IV • Answer the following Questions. 2 × 8 = 16

43. a) Construct a triangle similar to a given triangle PQR with its sides equal to 7/4 of the corresponding sides of the triangle PQR (Scale factor 7/4 > 1).
(OR) b) Construct a ΔPQR in which the base PQ = 4.5 Cm, ∠R = 35° and the median RG from R to PQ is 6 Cm.

44. a) A bus is travelling at a uniform speed of 50 km/hr. Draw the distance - time graph and hence find
    i) the constant of variation
    ii) how far will it travel in 90 minutes?
    iii) the time required to cover a distance of 300 km from the graph.
(OR) b) Draw the graph of xy = 24, x, y > 0. From the graph find,
    (i) y when x = 3 and (ii) x when y = 6.

QUARTERLY EXAM - 2026 • ANSWER KEY
Choose it:

1. c) 3

2. a) (8, 6)

3. a) 7

4. b) nm

5. c) 3

6. d) 11

7. a) 0

8. c) 14280

9. d) 16/5 |(x z2) / y|

10. b) 16x2

11. a) Straight line

12. b) 70°

13. b) 25 sq.u

14. c) 9

2 marks:

15. A = {1, 2, 3}, B = {2, 3, 5, 7}
A × B = {(1, 2), (1, 3), (1, 5), (1, 7), (2, 2), (2, 3), (2, 5), (2, 7), (3, 2), (3, 3), (3, 5), (3, 7)}
B × A = {(2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (3, 3), (5, 1), (5, 2), (5, 3), (7, 1), (7, 2), (7, 3)}

16. f(m) = m2 + m + 3
f(1) = 1 + 1 + 3 = 5
f(2) = 4 + 2 + 3 = 9
Different elements in N have different images in N.
It is one-one function.

17. f∁f(k) = 5
2(2k − 1) − 1 = 5
4k − 2 − 1 = 5
4k = 8 ⇒ k = 2

18. a = bq + r, 0 ≤ r < b
2 = 3(0) + 2
5 = 3(1) + 2
Ans: 2, 5, 8, 11, ...

19. LCM of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Ans: 2520

20. 104 ≡ x (mod 19)
(10)2 = 100 ≡ 5 (mod 19)
(10)4 ≡ 25 ≡ 6 (mod 19)
104 ≡ 6 (mod 19) ⇒ x = 6

21. t2 − t1 = t3 − t2
(18 − k) − (3 + k) = (5k + 1) − (18 − k)
15 − 2k = 6k − 17
8k = 32 ⇒ k = 4

22. Sn = (n / 2) [2a + (n − 1)d]
a = 1, d = 4
(n / 2) [2(1) + (n − 1)4] = 190
(n / 2) [4n − 2] = 190
2n2 − n − 190 = 0
(n − 10)(2n + 19) = 0
n = 10, n = −19/2 (not possible)

23. Area of ΔABC
= 1/2 | [−3, 1, −4, −3] over [−5, −1, 6, −5] |
= 1/2 [(3 + 6 + 20) − (−5 + 4 − 18)]
= 1/2 (48) = 24 sq.u

24. [(4x2y) / (2z2)] × [(6xz3) / (20y4)] = (3x3z) / (5y3)

25. x2 + 8x − 65 = 0
Sum = −b / a = −8 / 1 = −8
Product = c / a = −65

26. Area ΔDEF = (16 × 54) / 9 = 96 cm2

27. (y − y1) / (y2 − y1) = (x − x1) / (x2 − x1)
(y − 3) / (−1 − 3) = (x − 2) / (−7 − 2)
(y − 3) / (−4) = (x − 2) / (−9)
4x − 9y + 19 = 0

28. 13824 = 2a × 3b
13824 = 29 × 33 ⇒ a = 9, b = 3

5 marks:

29. A = {1, 2, 3, 4, 5, 6, 7}
B = {2, 3, 5, 7}
C = {2}
A ∩ B = {2, 3, 5, 7}
(A ∩ B) × C = {(2, 2), (3, 2), (5, 2), (7, 2)}
A × C = {(1, 2), (2, 2), (3, 2), (4, 2), (5, 2), (6, 2), (7, 2)}
B × C = {(2, 2), (3, 2), (5, 2), (7, 2)}
(A × C) ∩ (B × C) = {(2, 2), (3, 2), (5, 2), (7, 2)}

30.
i) Set of ordered pairs: f = {(2, 0), (4, 1), (6, 2), (10, 4), (12, 5)}
ii) Table:
x2461012
f(x)01245
iii) Arrow diagram: A {2, 4, 6, 10, 12} → B {0, 1, 2, 4, 5, 9} (2→0, 4→1, 6→2, 10→4, 12→5)
iv) Graph: Plotting points (2, 0), (4, 1), (6, 2), (10, 4), (12, 5)

31.
f(4) = 10
f(−2) = 2
f(4) + 2f(1) = 10 + 2(−1) = 8
[f(1) − 3f(4)] / f(−3) = [−1 − 3(10)] / 1 = −31

32.
f∁g(x) = f[g(x)] = f(x2) = x2 − 4
(f∁g)∁h(x) = f∁g(3x − 5) = (3x − 5)2 − 4 — (1)
g∁h(x) = g(h(x)) = g(3x − 5) = (3x − 5)2
f∁(g∁h)(x) = (3x − 5)2 − 4 — (2)
(1) = (2) proved.

33.
113400 = 23 × 34 × 52 × 71
p1 = 2, x1 = 3
p2 = 3, x2 = 4
p3 = 5, x3 = 2
p4 = 7, x4 = 1

34.
(a − d) + a + (a + d) = 27 ⇒ 3a = 27 ⇒ a = 9
(a − d) × a × (a + d) = 288
(a2 − d2) × a = 288
(92 − d2) × 9 = 288
81 − d2 = 32 ⇒ d2 = 49 ⇒ d = ±7
Terms: 2, 9, 16 or 16, 9, 2

35. Sn = 5 + 55 + 555 + ... n terms
= 5 [1 + 11 + 111 + ... n terms]
= 5/9 [9 + 99 + 999 + ... n terms]
= 5/9 [(10 + 100 + 1000 + ...) − (1 + 1 + 1 + ...)]
= 5/9 [ {10(10n − 1) / (10 − 1)} − n ]
= 50/81 (10n − 1) − 5n/9

36. Area = 102 + 112 + ... + 242
= (12 + 22 + ... + 242) − (12 + 22 + ... + 92)
= [ {24(24 + 1)(2 × 24 + 1)} / 6 ] − [ {9(9 + 1)(2 × 9 + 1)} / 6 ]
= [ (24 × 25 × 49) / 6 ] − [ (9 × 10 × 19) / 6 ]
= 4900 − 285 = 4615 cm2

37. Area of quadrilateral ABCD
= 1/2 | [8, 5, −5, −4, 8] over [6, 11, 12, 3, 6] |
= 1/2 [(109) − (−49)] = 1/2 (158) = 79 sq. u

38.
3x − 2y + z = 2 — (1)
2x + 3y − z = 5 — (2)
(1) + (2) ⇒ 5x + y = 7 — (4)

2x + 3y − z = 5 — (2)
x + y + z = 6 — (3)
(2) + (3) ⇒ 3x + 4y = 11 — (5)

(4) × 4 ⇒ 20x + 4y = 28
− (5) ⇒ 3x + 4y = 11
17x = 17 ⇒ x = 1
sub in (4): 5(1) + y = 7 ⇒ y = 2
sub in (3): 1 + 2 + z = 6 ⇒ z = 3

39.
[1 / (x2 − 5x + 6)] + [1 / (x2 − 3x + 2)] − [1 / (x2 − 8x + 15)]
= [1 / ((x − 2)(x − 3))] + [1 / ((x − 2)(x − 1))] − [1 / ((x − 5)(x − 3))]
= [ (x − 1)(x − 5) + (x − 3)(x − 5) − (x − 1)(x − 2) ] / [ (x − 1)(x − 2)(x − 3)(x − 5) ]
= (x2 − 11x + 18) / [ (x − 1)(x − 2)(x − 3)(x − 5) ]
= [ (x − 9)(x − 2) ] / [ (x − 1)(x − 2)(x − 3)(x − 5) ]
= (x − 9) / [ (x − 1)(x − 3)(x − 5) ]

40.
Square root of 9x4 + 12x3 + 28x2 + ax + b:
Quotient line: 3x2 + 2x + 4
• 3x2 | 9x4 → 9x4 (subtract)
• 6x2 + 2x | 12x3 + 28x2 → 12x3 + 4x2 (subtract)
• 6x2 + 4x + 4 | 24x2 + ax + b → 24x2 + 16x + 16 (subtract)
Remainder = 0
Since it is a perfect square: a = 16, b = 16

41. Refer Book

42.
Given point (x1, y1) = (6, −2)
Points: A(6, 7) and B(2, −3)
Equation of line joining A and B:
(y − y1) / (y2 − y1) = (x − x1) / (x2 − x1)
(y − 7) / (−3 − 7) = (x − 6) / (2 − 6)
(y − 7) / (−10) = (x − 6) / (−4)
(y − 7) / 5 = (x − 6) / 2
2y − 14 = 5x − 30
5x − 2y − 16 = 0

Equation of perpendicular line is of the form:
2x + 5y + k = 0
Passes through (6, −2):
2(6) + 5(−2) + k = 0
12 − 10 + k = 0
2 + k = 0 ⇒ k = −2
Required equation: 2x + 5y − 2 = 0


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