10th Maths Quarterly Exam 2026 Question Paper & Answer Key | Chengalpattu District (EM)

Elevate your academic preparation with the official 10th Maths Quarterly Exam 2026 Question Paper paired with verified Answer Keys for Chengalpattu District. This district-level terminal evaluation offers Tamil Nadu Samacheer Kalvi state board students a strategic resource to test their algebraic speed, conceptual accuracy, and logical reasoning under timed conditions. The assessment provides thorough coverage of essential early-term topics, including Relations and Functions, Numbers and Sequences (AP/GP series), polynomial equations, and foundational Geometry theorems. Practicing with this specific regional paper and utilizing the detailed step-by-step answer keys will help you identify minor calculation traps, master the distribution of step-wise marks, and perfect the structured presentation needed to achieve a perfect centum score on your final board examinations.


10th Maths Quarterly Exam 2026 Question Paper & Answer Key | Chengalpattu District

CLASS: 10 Register Number: [____________]

COMMON QUARTERLY EXAMINATION - 2026 - 27

MATHEMATICS
Time Allowed: 3.00 Hours Max. Marks: 100
PART - I • I. Answer all of the following: 14 × 1 = 14

1. If n(A × B) = 6 and A = {1, 3} then n(B) is
a) 1      b) 2      c) 3      d) 6

2. Let n(A) = m and n(B) = n then the total number of non-empty relations that can be defined from A to B is
a) mn      b) nm      c) 2mn − 1      d) 2mn

3. Given f(x) = (−1)x is a function from N to Z, then the range of f is
a) {1}      b) N      c) {1, −1}      d) Z

4. The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is
a) 2025      b) 5220      c) 5025      d) 2520

5. 74k ≡ _______ (mod 100)
a) 1      b) 2      c) 3      d) 4

6. The value of (13 + 23 + 33 + ... + 153) − (1 + 2 + 3 + ... + 15) is
a) 14400      b) 14200      c) 14280      d) 14520

7. If (x − 6) is the HCF of x2 − 2x − 24 and x2 − kx − 6 then the value of k is
a) 3      b) 5      c) 6      d) 8

8. Graph of a linear equation is a
a) Straight line      b) Circle      c) Parabola      d) Hyperbola

9. If a3 / (a − b) is added with b3 / (b − a) then the new expression?
a) a2 + ab + b2      b) a2 − ab + b2      c) a3 + b3      d) a3 − b3

10. The perimeters of two similar triangles ΔABC and ΔPQR are 36 cm and 24 cm respectively. If PQ = 10 cm then the length of AB is
a) 6 2/3 cm      b) (10√6) / 3 cm      c) 66 2/3 cm      d) 15 cm

11. In a ΔABC, AD is the bisector of ∠BAC. AB = 8 cm, BD = 6 cm, and DC = 3 cm, the length of the side AC is
a) 6 cm      b) 4 cm      c) 3 cm      d) 8 cm

12. The point of intersection of 3x − y = 4 and x + y = 8 is
a) (5, 3)      b) (2, 4)      c) (3, 5)      d) (4, 4)

13. If slope of the line PQ is 1 / √3 then slope of perpendicular bisector of PQ is
a) √3      b) −√3      c) 1 / √3      d) 0

14. If x = a tan θ and y = b sec θ then
a) (y2 / b2) − (x2 / a2) = 1      b) (x2 / a2) − (y2 / b2) = 1
c) (x2 / a2) + (y2 / b2) = 1      d) (x2 / a2) − (y2 / b2) = 0

PART - II • II. Answer any 10 questions (Question No. 28 is compulsory): 10 × 2 = 20

15. Let A = {1, 2, 3, 4, ..., 45} and R be the relation defined as "square of a number" on A. Write R as a subset of A × A. Also, find the domain and range of R.

16. If f(x) = 3x − 2, g(x) = 2x + k and if f ∁ g = g ∁ f then find the value of k.

17. a and b are two positive integers, such that ab × ba = 800. Find a and b.

18. Find the sum of 1 + 4 + 9 + 16 + ... + 225.

19. Find the excluded values of: (x2 + 6x + 8) / (x2 + x − 2).

20. If the difference between a number and its reciprocal is 24/5, Find the number.

21. If α, β are the roots of the equation 3x2 + 7x − 2 = 0, find the value of (α / β) + (β / α).

22. If ΔABC ~ ΔDEF such that area of ΔABC is 9 cm2 and the area of ΔDEF is 16 cm2. If BC = 2.1 cm, find the length of EF.

23. In a ΔABC, AD is the bisector of ∠BAC. If AB = 10 cm, AC = 14 cm and BC = 6 cm, find BD and DC.

24. Find the slope of a line joining the points (5, √5) and Origin.

25. Find the equation of line passing through the point (3, −4) and having slope −5/7.

26. Find the intercepts made by the line 4x + 3y + 12 = 0 on the coordinate axes.

27. Prove that √[(1 + cos θ) / (1 − cos θ)] = cosec θ + cot θ.

28. [Compulsory] The ratio of three numbers is 2:5:7. If 7 is subtracted from the second number, the resulting three numbers are in A.P. Find the numbers.

PART - III • III. Answer any 10 of the following questions (Q.No. 42 is compulsory): 10 × 5 = 50

29. Let A = {x ∈ W | x < 2}, B = {x ∈ N | 1 < x ≤ 4} and C = {3, 5}. Verify that A × (B ∪ C) = (A × B) ∪ (A × C).

30. Let A = {1, 2, 3, 4} and B = {2, 5, 8, 11, 14} be two sets. Let f: A → B be a function given by f(x) = 3x − 1. Represent this function (i) by arrow diagram (ii) in a table form (iii) as a set of ordered pairs (iv) a graph.

31. The function 't' which maps temperature in Celsius (C) into temperature in Fahrenheit (F) is defined by t(C) = F where F = 9/5C + 32. Find:
(i) t(0)      (ii) t(28)      (iii) t(−10)
(iv) the value of C when t(C) = 212
(v) the temperature when the Celsius value is equal to the Fahrenheit value.

32. If p1x1 × p2x2 × p3x3 × p4x4 = 113400, where p1, p2, p3, p4 are primes in ascending order and x1, x2, x3, x4 are integers, find the value of p1, p2, p3, p4 and x1, x2, x3, x4.

33. Find the sum of all natural numbers between 300 and 600 which are divisible by 7.

34. Find the sum to n terms of the series 3 + 33 + 333 + ...

35. Solve: 3x − 2y + z = 2,   2x + 3y − z = 5,   x + y + z = 6.

36. If 36x4 − 60x3 + 61x2 − mx + n is a perfect square, find the values of m and n.

37. If the roots of the equation (c2 − ab)x2 − 2(a2 − bc)x + b2 − ac = 0 are real and equal, prove that either a = 0 or a3 + b3 + c3 = 3abc.

38. State and prove Thales Theorem.

39. Find the area of the quadrilateral formed by the points (8, 6), (5, 11), (−5, 12) and (−4, 3).

40. If the vertices of a ΔABC are A(6, 2), B(−5, −1) and C(1, 9). Through the vertex A, find the equation of the median.

41. If cos α / cos β = m and cos α / sin β = n, then prove that (m2 + n2)cos2β = n2.

42. [Compulsory] Find the equation of a line passing through the point of intersection of the lines 4x + 7y − 3 = 0 and 2x − 3y + 1 = 0 that has equal intercepts on the axes.

PART - IV • IV. Answer the following: 2 × 8 = 16

43. a) Construct a triangle similar to a given triangle ΔPQR with its sides equal to 3/5 of the corresponding sides of the triangle PQR (scale factor 3/5 < 1).
(OR) b) Construct a ΔPQR such that QR = 6.5 cm, ∠P = 60° and the altitude from P to QR is of length 4.5 cm.

44. a) A bus is traveling at a uniform speed of 50 km/hr. Draw the time-distance graph and hence find:
(i) the constant of variation
(ii) how far will it travel in 90 minutes?
(iii) the time required to cover a distance of 300 km from the graph.
(OR) b) Draw the graph of xy = 24, x, y > 0. Using the graph find:
(i) y when x = 3 and
(ii) x when y = 6.
ANSWER KEY & COMPLETE SOLUTIONS
PART - I:

1. c) 3

2. c) 2mn − 1

3. c) {1, −1}

4. d) 2520

5. a) 1

6. c) 14280

7. b) 5

8. a) Straight line

9. a) a2 + ab + b2

10. d) 15 cm

11. b) 4 cm

12. c) (3, 5)

13. b) −√3

14. a) (y2 / b2) − (x2 / a2) = 1

PART - II:

15. A = {1, 2, 3, 4, ..., 45}. Relation R: "square of a number" on A.
R = {(1, 1), (2, 4), (3, 9), (4, 16), (5, 25), (6, 36)} ⊂ A × A
Domain of R = {1, 2, 3, 4, 5, 6}
Range of R = {1, 4, 9, 16, 25, 36}

16. f(x) = 3x − 2,   g(x) = 2x + k
f ∁ g(x) = f(2x + k) = 3(2x + k) − 2 = 6x + 3k − 2
g ∁ f(x) = g(3x − 2) = 2(3x − 2) + k = 6x − 4 + k
f ∁ g = g ∁ f ⇒ 6x + 3k − 2 = 6x − 4 + k ⇒ 2k = −2 ⇒ k = −1

17. ab × ba = 800
800 = 25 × 52
Comparing terms: a = 2, b = 5 (or a = 5, b = 2)

18. 1 + 4 + 9 + 16 + ... + 225 = 12 + 22 + 32 + ... + 152
Formula: Σ n2 = [n(n + 1)(2n + 1)] / 6
= [15 × 16 × 31] / 6 = 5 × 8 × 31 = 1240

19. (x2 + 6x + 8) / (x2 + x − 2) = [(x + 4)(x + 2)] / [(x + 2)(x − 1)]
Setting denominator to zero: x2 + x − 2 = 0 ⇒ (x + 2)(x − 1) = 0
Excluded values: −2, 1

20. Let the number be x. x − 1/x = 24/5 ⇒ (x2 − 1)/x = 24/5
5x2 − 24x − 5 = 0 ⇒ (x − 5)(5x + 1) = 0
x = 5 or x = −1/5

21. 3x2 + 7x − 2 = 0 ⇒ α + β = −7/3,   αβ = −2/3
(α / β) + (β / α) = (α2 + β2) / αβ = [(α + β)2 − 2αβ] / αβ
= [(−7/3)2 − 2(−2/3)] / (−2/3) = (49/9 + 4/3) / (−2/3) = (61/9) × (−3/2) = −61/6

22. ΔABC ~ ΔDEF ⇒ Area(ΔABC) / Area(ΔDEF) = BC2 / EF2
9 / 16 = (2.1)2 / EF2 ⇒ 3 / 4 = 2.1 / EF
3 EF = 8.4 ⇒ EF = 2.8 cm

23. By Angle Bisector Theorem, BD / DC = AB / AC = 10 / 14 = 5 / 7
BC = 6 cm ⇒ BD = 6 × (5 / 12) = 2.5 cm
DC = 6 × (7 / 12) = 3.5 cm

24. Slope m = (y2 − y1) / (x2 − x1) = (√5 − 0) / (5 − 0) = √5 / 5 = 1 / √5

25. y − y1 = m(x − x1) ⇒ y − (−4) = −5/7 (x − 3)
7(y + 4) = −5(x − 3) ⇒ 7y + 28 = −5x + 15
5x + 7y + 13 = 0

26. 4x + 3y = −12 ⇒ 4x / (−12) + 3y / (−12) = 1
x / (−3) + y / (−4) = 1
x-intercept = −3,   y-intercept = −4

27. LHS = √[ ((1 + cos θ)(1 + cos θ)) / ((1 − cos θ)(1 + cos θ)) ] = √[ (1 + cos θ)2 / sin2θ ]
= (1 + cos θ) / sin θ = (1 / sin θ) + (cos θ / sin θ) = cosec θ + cot θ = RHS. Hence proved.

28. Let the numbers be 2x, 5x, 7x.
Given 2x, 5x − 7, 7x are in A.P.
2(5x − 7) = 2x + 7x ⇒ 10x − 14 = 9x ⇒ x = 14
The numbers are 2(14), 5(14), 7(14) = 28, 70, 98

PART - III:

29. A = {0, 1}, B = {2, 3, 4}, C = {3, 5}
B ∪ C = {2, 3, 4, 5}
LHS: A × (B ∪ C) = {(0, 2), (0, 3), (0, 4), (0, 5), (1, 2), (1, 3), (1, 4), (1, 5)} — (1)
A × B = {(0, 2), (0, 3), (0, 4), (1, 2), (1, 3), (1, 4)}
A × C = {(0, 3), (0, 5), (1, 3), (1, 5)}
RHS: (A × B) ∪ (A × C) = {(0, 2), (0, 3), (0, 4), (0, 5), (1, 2), (1, 3), (1, 4), (1, 5)} — (2)
From (1) and (2), A × (B ∪ C) = (A × B) ∪ (A × C) is verified.

30. f(x) = 3x − 1, A = {1, 2, 3, 4}, B = {2, 5, 8, 11, 14}
f(1) = 2, f(2) = 5, f(3) = 8, f(4) = 11
(i) Arrow diagram: 1→2, 2→5, 3→8, 4→11
(ii) In a table form:
x1234
f(x)25811
(iii) Set of ordered pairs: f = {(1, 2), (2, 5), (3, 8), (4, 11)}
(iv) A graph: Plot the points (1, 2), (2, 5), (3, 8), (4, 11) on coordinate axes.

31. t(C) = 9/5 C + 32
(i) t(0) = 9/5(0) + 32 = 32°F
(ii) t(28) = 9/5(28) + 32 = 50.4 + 32 = 82.4°F
(iii) t(−10) = 9/5(−10) + 32 = −18 + 32 = 14°F
(iv) 9/5 C + 32 = 212 ⇒ 9/5 C = 180 ⇒ C = 100°C
(v) C = F ⇒ C = 9/5 C + 32 ⇒ −4/5 C = 32 ⇒ C = −40°

32. 113400 = 23 × 34 × 52 × 71
Primes in ascending order: p1 = 2, p2 = 3, p3 = 5, p4 = 7
Exponents: x1 = 3, x2 = 4, x3 = 2, x4 = 1

33. Numbers divisible by 7 between 300 and 600: 301, 308, 315, ..., 595
a = 301, d = 7, l = 595
n = [(l − a) / d] + 1 = [(595 − 301) / 7] + 1 = (294 / 7) + 1 = 42 + 1 = 43
S43 = (43 / 2)[301 + 595] = (43 / 2)(896) = 43 × 448 = 19264

34. Sn = 3 + 33 + 333 + ... to n terms
= 3(1 + 11 + 111 + ... to n terms) = 3/9 (9 + 99 + 999 + ... to n terms)
= 1/3 [(10 − 1) + (102 − 1) + ... + (10n − 1)]
= 10/27 (10n − 1) − n/3

35. 3x − 2y + z = 2 — (1),   2x + 3y − z = 5 — (2),   x + y + z = 6 — (3)
(1) + (2) ⇒ 5x + y = 7 — (4)
(2) + (3) ⇒ 3x + 4y = 11 — (5)
4 × (4) − (5) ⇒ 20x − 3x = 28 − 11 ⇒ 17x = 17 ⇒ x = 1
From (4): 5(1) + y = 7 ⇒ y = 2
From (3): 1 + 2 + z = 6 ⇒ z = 3
Solution: x = 1, y = 2, z = 3

36. 36x4 − 60x3 + 61x2 − mx + n is a perfect square.
Square root by division gives quotient: 6x2 − 5x + 3
(6x2 − 5x + 3)2 = 36x4 − 60x3 + 61x2 − 30x + 9
Comparing terms: m = 30,   n = 9

37. Roots are real and equal ⇒ Δ = B2 − 4AC = 0
[−2(a2 − bc)]2 − 4(c2 − ab)(b2 − ac) = 0
4[(a4 − 2a2bc + b2c2) − (b2c2 − ac3 − ab3 + a2bc)] = 0
a4 − 3a2bc + ab3 + ac3 = 0 ⇒ a(a3 + b3 + c3 − 3abc) = 0
Hence, either a = 0 or a3 + b3 + c3 = 3abc. Hence proved.

38. Thales Theorem: Statement and Proof (Refer standard textbook).

39. Points: (8, 6), (5, 11), (−5, 12), (−4, 3)
Area = 1/2 [(88 + 60 − 15 − 24) − (30 − 55 − 48 + 24)] = 1/2 [109 − (−49)] = 1/2 (158) = 79 sq. units

40. Midpoint of BC where B(−5, −1) and C(1, 9): D = [(−5 + 1)/2, (−1 + 9)/2] = (−2, 4)
Equation of median AD passing through A(6, 2) and D(−2, 4):
(y − 2) / (4 − 2) = (x − 6) / (−2 − 6) ⇒ (y − 2) / 2 = (x − 6) / (−8)
−4(y − 2) = x − 6 ⇒ −4y + 8 = x − 6 ⇒ x + 4y − 14 = 0

41. m = cos α / cos β,   n = cos α / sin β
LHS = (m2 + n2)cos2β = [ (cos2α / cos2β) + (cos2α / sin2β) ] cos2β
= cos2α [ (sin2β + cos2β) / (cos2β sin2β) ] cos2β = cos2α [ 1 / (cos2β sin2β) ] cos2β
= cos2α / sin2β = (cos α / sin β)2 = n2 = RHS. Hence proved.

42. Intersection of 4x + 7y − 3 = 0 and 2x − 3y + 1 = 0:
Multiply second equation by 2: 4x − 6y + 2 = 0
Subtracting gives: 13y − 5 = 0 ⇒ y = 5/13
2x = 3(5/13) − 1 = 2/13 ⇒ x = 1/13
Line with equal intercepts: x + y = a
a = 1/13 + 5/13 = 6/13
Equation: x + y = 6/13 ⇒ 13x + 13y − 6 = 0

PART - IV:

43. a) Similar triangle construction with scale factor 3/5 < 1 • b) ΔPQR construction with QR = 6.5 cm, ∠P = 60°, and altitude from P to QR of length 4.5 cm.

44. a) Bus travelling at 50 km/hr (Direct variation: y = kx):
(i) Constant of variation: k = y / x = 50 / 60 = 5/6
(ii) Distance travelled in 90 minutes: y = (5/6) × 90 = 75 km
(iii) Time required to cover 300 km: x = 300 × (6/5) = 360 minutes (6 hours)
44. b) Graph of xy = 24 (Inverse variation):
(i) When x = 3 ⇒ y = 24 / 3 = 8
(ii) When y = 6 ⇒ x = 24 / 6 = 4

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